Benda Bermassa 1 Kg Ditarik Oleh Gaya Mendatar Sebesar 2 Newton Dari Keadaan Diam,Jarak Yag Ditempuh Benda Dalam Waktu 10 Sekon Adalah

benda bermassa 1 kg ditarik oleh gaya mendatar sebesar 2 Newton dari keadaan diam,jarak yag ditempuh benda dalam waktu 10 Sekon adalah

Answer:

The distance is 100 meters

Explanation:

In our case, objects with a given mass were pulled along the horizontal axis with a given force. This problem statement is a combination of Newtons 2nd Law of motion and Motion in a Straight Line.

To solve this, we will use the formula:

a. F = ma

where

F     is the force, unit is in Newtons (N)

m    is the mass, unit is in kg

a     is the acceleration, unit is in m/s^2

b. x=v_{0} t+\frac{1}{2} at^2

where

x     is the distance traveled by the object, unit is in meter (m)

v_{0}    is the initial velocity, unit is in m/s

t      is the time, unit is in seconds (s)

For the given information

a. The mass of the objects is, m= 1 kg

b. The force  pulling the objects is, F = 2N

c. The time covered in pulling the objects were, t = 10 seconds

Solving the problem

1. First, use the formula for force

F = ma

Substitute the given information

2N = (1kg) a

Divide both sides of the equation by 1 kg, we have:

\frac{2N}{1kg} =\frac{(1kg)a}{1kg}

Then to solve for the acceleration, we have:

a = 2 m/s^2

2. Now, we are ready to solve the distance.

Use the second formula and substitute the given information, we have:

x=v_{0} t+\frac{1}{2} at^2

x=0+\frac{1}{2} (2m/s^2)(10)^2

Take note that v_{0} t is zero because v_{0} = 0 (or the initial velocity starts from rest).

Simplifying the equation, we have:

x=\frac{1}{2} (2)(10)^2

x = 100 meters

Therefore, the distance traveled by the 1 kg objects in 10 seconds is 100 meters.

To learn more about this topic, just click on the following links:

  • Example of 2nd Newtons Law of motion

       brainly.ph/question/128165

  • Additional example

       brainly.ph/question/2103817

#LetsStudy


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